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Old Sep 30th, 2018, 16:36   #1
arcturus
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Ron. I obtained this doc' on charging systems. Can you explain the difference between "current reg" and "voltage reg" on the voltage regulator in reference to the three relays.

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Old Oct 1st, 2018, 11:38   #2
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To elaborate, Terminal B+ is cut out relay. Terminal DF Current regulator
Terminal D+ voltage regulator.
Can you explain please the function of each relay.
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Old Oct 1st, 2018, 13:41   #3
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Arcturus;

I have careful reviewed the article...it is generally good and consists of much good and valid info...the only minor issue I have with it is where it states in the second paragraph: "When the armature spins in the magnetic field, the windings in the armature have a voltage induced in them"...more correctly, it should state: "have a current induced in them"...this is a point of physics, but since voltage and current are related, the author mixed the terms...again, otherwise it is a good article, and good reading for anyone wanting to understand their Chg Sys better.

To answer your question...Voltage Regulation is when the VReg monitors system voltage and when low, enables Charging System to generate and contribute power...which pulls up system voltage as it recharges Bat and powers loads. Current Regulation is rather a safety function of the VReg...it monitors the Gen output current and if too high (so that it might damage Ch Sys) it has the ability to decrease the (Field) energization current, which in turn, backs down the Gen output and lowers the stresses put on it...it may therefore take longer to recharge a highly discharged Bat, but that is always preferable to overloading the Gen and risking damaging it...

Hope that helps... Cheers

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Old Oct 2nd, 2018, 23:35   #4
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Quote:
Originally Posted by Ron Kwas View Post
it states in the second paragraph: "When the armature spins in the magnetic field, the windings in the armature have a voltage induced in them"...more correctly, it should state: "have a current induced in them".
Sorry Ron - but voltage is correct. V = N d(phi)/dt, as Faraday might have said if he'd had to do it on a keyboard

(Consider the case when there is no load connected - no current flows, but you get the voltage anyway.)
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Old Oct 3rd, 2018, 14:04   #5
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Pigeon;

I tried to answer arcturus' question and explain things in an understandable manner...you and I can have a theoretical discussion beyond that, but it will surely be lost on non-engineers...as I noted...V and I are (very!) related, and in your special example of an open circuit, clearly there can be no current flowing as there is no complete path (i.e. "circuit"), so the voltage will certainly build and one could say "voltage is induced".

As engineers, I think we understand each other...I was always taught, and come back to the term "current is induced...", as it is presented in theoretical discussions, such as here: https://www.khanacademy.org/science/...ng-electricity

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Old Oct 3rd, 2018, 16:19   #6
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Whilst we are on the subject of electrics, I am having some problems with my lights. i think that the dip switch may be faulty. When I connect my volt meter to the power terminal I get 6+ volts from the other terminal that supply's power to the lamp,main for example. The other terminal out to dip shows .06v. Is that enough leakage between terminals to cause a problem or is it negligible? This is on both main and dip positions. Should I replace the switch?
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Old Oct 3rd, 2018, 19:43   #7
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arcturus;

That "leakage voltage" is a mere 1% of the system voltage and nothing to be concerned about!...if the voltage was to increase to something more substantial, the Dipper Switch is not what I'd suspect first, but the chassis connections at the headlights! This would be an example of voltage drops due to a poor chassis connection causing an inadvertent circuit interaction...I'll see if I can sketch up an explanation...

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Old Oct 4th, 2018, 09:18   #8
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Thanks. i know that you provided me with a fuse size calculator some time ago but can't find it. Can you please send repeat. Thanks.
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Old Oct 4th, 2018, 10:02   #9
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Quote:
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Sorry Ron - but voltage is correct. V = N d(phi)/dt, as Faraday might have said if he'd had to do it on a keyboard

(Consider the case when there is no load connected - no current flows, but you get the voltage anyway.)
Indeed you can't get current ( flow ) started without voltage ( pressure)
but you can get voltage without current .
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Old Oct 4th, 2018, 11:56   #10
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I had a battery failure where it still showed 12.6 volts but could only supply about 8 amps. The nice AA man sold me a new battery.
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